I was wondering if it was possible to change the year format from e.g. 2005 to 2548?

Thanks

function convert_date($dateR){
$engMon=array('January','February','March','April','May','June','July' ,'August','September','October','November','December',' ');
$months=explode (':', $GLOBALS['l_months']);
$months[]=' ';
$year=date('Y',strtotime($dateR))+543;
$GLOBALS['dateFormat']=str_replace('Y', $year, $GLOBALS['dateFormat']);
if(isset($GLOBALS['timeDiff']) and $GLOBALS['timeDiff']!=0) $dateR=date($GLOBALS['dateFormat'],strtotime($dateR)+$GLOBALS['timeDif f']);
else $dateR=date($GLOBALS['dateFormat'],strtotime($dateR));
$dateR=str_replace($engMon,$months,$dateR);
return $dateR;
}

cursived are new strings.

Thank for your reply.
I copied your new function convert_date to bb_function.php

It still does not work!
Year is still 2005

Don't copy the whole function, just insert 2 new lines in the old function.

It should work. I've checked on my server and it works.

Excuse me for the input, I only became curious, why is that the year to be another year after 500 years? :)

To Ivan
Because my buddha year is 2548.
So I need to +543 years more form Jessus year.

To Team
I tried to add this 2 lines
$year=date('Y',strtotime($dateR))+543;
$GLOBALS['dateFormat']=str_replace('Y', $year, $GLOBALS['dateFormat']);

It still does not work again.
Do you have the other way?
Anyway Thank a millions

Which $dateFormat setting do you have?

You need to have 'Y' inside of it.

My example:

$dateFormat='j F Y H:i';

I got it!
Thank You So Much.

I have another question.
If I want to show only 48 insted of 2548.
How could I do?
Thank in advance.

$GLOBALS['dateFormat']=str_replace('Y', substr($year,-2), $GLOBALS['dateFormat']);

Thank You So Much
You did very good job!